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0=3x^2+5x-6
We move all terms to the left:
0-(3x^2+5x-6)=0
We add all the numbers together, and all the variables
-(3x^2+5x-6)=0
We get rid of parentheses
-3x^2-5x+6=0
a = -3; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·(-3)·6
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{97}}{2*-3}=\frac{5-\sqrt{97}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{97}}{2*-3}=\frac{5+\sqrt{97}}{-6} $
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